Question
A trader sells an item at a profit of 20%. If he had
bought it for 10% less and sold it for Rs 30 less than his original selling price, his profit would have been 25%. Find the original cost price of the item.Solution
Let original cost price = C. Original selling price = 1.20C. If he had bought it 10% cheaper: new cost price = 0.90C. New selling price = (original SP − 30) = 1.20C − 30. This new selling price gives 25% profit on new cost: 1.20C − 30 = 1.25 × 0.90C = 1.125C So: 1.20C − 1.125C = 30 0.075C = 30 C = 30 / 0.075 = 400 Answer: Original cost price = Rs 400.
If √y + (1/√y) = 10, then find the value of y + (1/y).
if a2 + b2 + c2 = 2(4a -5b -6c)-77 , then a-b-c = ?
Simplify:
7x + 9y - [(14x + 5y) - (5x + 3y) + 4y] - 5x
= ?In an A.P 41st term is 50, then the sum of 81 terms of that A.P is:
(3x × 9(x+1)) / 27(2x–1) = 1, then find 'x'.
If (54√2 x³ +24√3 y³)÷(√18 x + √12 y) = Ax² + By² + Cxy, then what is the value of A² - (B²...
If √r + (1/√r) = 4, then find the value of r + (1/r).
- If x² - 2x + 1 = 0, then find the value of (x² + x⁻²)(x³ + x⁻³).
{(21/20) + (20/21)}2 - {(21/20) - (20/21)}2 = ?