Question
The cost price of machine X is Rs. 600 more than the
cost price of machine Y. Machine X is sold at a profit of 25%, and machine Y is sold at a profit of 40%. If their selling prices are equal, find the cost price of machine X.Solution
ATQ, Let the cost price of machine Y = x Cost price of machine X = x + 600 According to the question, (x+600) 125/100 = x140/100 25x + 15000 = 28x 3x = 15000 x = 5000 Cost price of machine X = 5000 + 600 = Rs.5600 Required answer = Rs.5600
20.02% of (95.96 × 104.01 – 56.02 × 64.04) – ? = 12.02 × 39.96 + 103.03
32.052- 22.03 x 24.199 - 15.18 x 11.04 = ?
15.98% of 2199.9 = √? + 17.02% of 1799.97
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(20.98 ÷ 2.91) + (15.12 – 5.96) = ?Â
510.11 ÷ 16.98 × 5.14 – 119.9 = √?Â
{(1799.89 ÷ 8.18) ÷ 9.09 + 175.15} = 25.05% of ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?