Question
The cost price of a product is Rs. (10n + 200). It is
marked 30% above its cost price and sold after allowing a discount of Rs. (2n + 20). If the profit earned is Rs. 980, then find the value of 'n'.Solution
ATQ,
Marked price = 1.3 × (10n + 200) = Rs. (13n + 260)
Selling price = (13n + 260) - (2n + 20) = Rs. (11n + 240)
Profit = (11n + 240) - (10n + 200) = Rs. (n + 40)
So, n + 40 = 980
Or, n = 940
More Profit and loss Questions
Simplify: 6(x³ − 2x² + 3x) − (x³ + 2x − 3).
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
20 * 8 + 40% of 100 + 60% of 150 = ?
(64 × 16) ÷ (4 × 16) 3 × 256 2 = 4 ?
25% of 1000 + 10% of 150 – 22 × ? = 45
390/? = √256 + 3.5
4.7 × 3.5 + 4.2 × 4.5 = 22.5 × 3.5 - ?
540240 ÷ 24 ÷ 25 =?
Simplify-
x + 3(y + x – 2) – (x + y).
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