Question
'P' sells a product to
'Q' at a profit of 'y%' . Then, 'Q' sells it to 'R' at a loss of (y + 10)% . 'R' pays Rs. 360 to 'Q', and 'P' had originally bought the product for Rs. 480 . If 'P' had instead sold it to 'S' at a profit of (y/5)% , find the amount paid by 'S' to 'P'.Solution
ATQ, 480 × [(100 + y)/100] × [(100 - y - 10)/100] = 360 [(100 + y)/100] × [(90 - y)/100] = 0.75 9000 + 100y - 90y - y² = 7500 y² - 10y - 1500 = 0 y² - 50y + 40y - 1500 = 0 y(y - 50) + 40(y - 50) = 0 (y - 50)(y + 40) = 0 y = 50 or -40 Profit can't be negative ⇒ y = 50 Now, profit for selling to 'S' = y/5 = 10% Required amount = 480 × 1.10 = Rs. 528
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Seven persons R, S, T, U, V, W and X has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. S has exam on ...
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Conclusions:
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