Question
Cost price of a CPU is 12.5% less than the marked price of
tablet which is 36% less than the marked price of the CPU. The tablet is sold at 20profit after allowing a discount of 6.25% and CPU is sold at 7(1/7)% profit. If the discount given on CPU is 'p'% and tablet was marked up by 'q'%, then which of the following options is true regarding 'p' and 'q'.Solution
Let the marked price of tablet be Rs 16x.
So, marked price of CPU = Rs. 16x X (100/64) = Rs. 25x
So, cost price of CPU = 16x X (7/8) = Rs. 14x
Selling price of the tablet = 16x X (15/16) = Rs. 15x
Selling price of the CPU = 14x X (8/7) = Rs. 16x
Cost price of the tablet = Rs. 15x X (5/6) = Rs. 12.5x
So, discount given on CPU = {(25x - 16x) /25x} X 100 = 36%
Or, 'p' = 40
Percentage by which the tablet was marked up = {(16x - 12.5x) /12.5} X 100 = 28%
Or, q = 28
From (I)
Both 'p' and 'q' are less than 50.
So, (I) is not true.
From (II)
'q' is not a multiple of 10
So, (II) is not true.
From (III)
P ≠ q
So, (III) is not true.
From (IV)
'q' is not greater than 'p'
So, (IV) is not true.
From (V)
'p' > 'q'
So, (V) is true
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the given expression:
(125 - 75 ÷ 3 of 5) ÷ 2 + 4 of 12 ÷ 3 - 16 of 5 ÷ 20
70 % of 640 + 75 % of 360 - 19 × 12 = ?
- Find the simplified value of following expression:
0.998 + 0.882 + 0.12 (√1296 – 12) × 5 = ? + 40
?% of (168 ÷ 8 × 20) = 126
458.32-563.32+659.32=?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
[(40)2 ÷ 32 × 4] ÷ 50 = ?