New Enroll here to Join NaBFID Analyst Into Class on May 6

    Question

    The average cost price of articles 'M' and 'N' together is

    Rs. 500 where the cost price of article 'N' is Rs. 100 more than that of article 'M'. If articles 'M' and 'N' are sold at profit of 15% and profit of 10%, respectively, then find the difference between their selling prices.
    A Rs.50.5 Correct Answer Incorrect Answer
    B Rs.62.5 Correct Answer Incorrect Answer
    C Rs.43.5 Correct Answer Incorrect Answer
    D Rs.87.5 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the cost price of article 'M' = Rs. '10x'

    Then, cost price of article 'N' = Rs. (10x + 100)

    Sum of cost price of articles 'M' and 'N' = 10x + 10x + 100 = Rs. (20x + 100) = 500 × 2

    Or, 20x + 100 = 1000

    Or, 20x = 900

    Or, x = 45

    Cost price of articles 'M' and 'N' are Rs. 450 and Rs. 550, respectively

    Selling price of article 'M' = 450 × 1.15 = Rs. 517.5

    Selling price of article 'N' = 550 × 1.1 = Rs. 605

    Required difference = 605 - 517.5 = Rs. 87.5

    Practice Next