Start learning 50% faster. Sign in now
ATQ,
Let the cost price of article 'M' = Rs. '10x'
Then, cost price of article 'N' = Rs. (10x + 100)
Sum of cost price of articles 'M' and 'N' = 10x + 10x + 100 = Rs. (20x + 100) = 500 × 2
Or, 20x + 100 = 1000
Or, 20x = 900
Or, x = 45
Cost price of articles 'M' and 'N' are Rs. 450 and Rs. 550, respectively
Selling price of article 'M' = 450 × 1.15 = Rs. 517.5
Selling price of article 'N' = 550 × 1.1 = Rs. 605
Required difference = 605 - 517.5 = Rs. 87.5
The sum of the exponents of the prime factors in the prime factorization of 225 is
X is 10 ft tall, and he notices that he casts a shadow that's 3 ft long. He then measures that the shadow cast by his school building is 30 ft long. How...
The ratio between two numbers is 2:3 and the sum of their squares is 2197. The numbers are:
Out of 3 √4, √2, 6 √3, 4 √5 which number is the biggest?
Find the remainder when the number (289n + 147) is divided by 17.
How many integers are there between 50 and 600 that are divisible by both 15 and 25?
The sum of three consecutive odd natural numbers each divisible by 3 is 81. Which number is the largest number among the three numbers?
Find the sum of all two-digit numbers that are exactly divisible by 6.