Question
The average cost price of articles 'M' and 'N' together is
Rs. 500 where the cost price of article 'N' is Rs. 100 more than that of article 'M'. If articles 'M' and 'N' are sold at profit of 15% and profit of 10%, respectively, then find the difference between their selling prices.Solution
ATQ,
Let the cost price of article 'M' = Rs. '10x'
Then, cost price of article 'N' = Rs. (10x + 100)
Sum of cost price of articles 'M' and 'N' = 10x + 10x + 100 = Rs. (20x + 100) = 500 × 2
Or, 20x + 100 = 1000
Or, 20x = 900
Or, x = 45
Cost price of articles 'M' and 'N' are Rs. 450 and Rs. 550, respectively
Selling price of article 'M' = 450 × 1.15 = Rs. 517.5
Selling price of article 'N' = 550 × 1.1 = Rs. 605
Required difference = 605 - 517.5 = Rs. 87.5
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