Question
The average cost price of articles 'C' and 'D' together is
Rs. 350 where the cost price of article 'D' is Rs. 40 more than that of article 'C'. If articles 'C' and 'D' are sold at profit of 18% and profit of 22%, respectively, then find the difference between their selling prices.Solution
ATQ,
Let the cost price of article 'C' = Rs. '10x'
Then, cost price of article 'D' = Rs. (10x + 40)
Sum of cost price of articles 'C' and 'D' = 10x + 10x + 40 = Rs. (20x + 40) = 350 × 2
Or, 20x + 40 = 700
Or, 20x = 660
Or, x = 33
Cost price of articles 'C' and 'D' are Rs. 330 and Rs. 370, respectively
Selling price of article 'C' = 330 × 1.18 = Rs. 389.4
Selling price of article 'D' = 370 × 1.22 = Rs. 451.4
Required difference = 451.4 - 389.4 = Rs. 62
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...3720 3842 ? 4092 4220 4350
22 44 176 1078 8448
...3456 1728 2592 6485 22680 102060
...5                             6                             14              �...
Identify the logic of the below given series and given answer.
Series I :: 81, 89, 116, 241, (A), 1915
Series II :: (B), 204, 208, 4...
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...If 24 33 x 42 6 51
Then, 20% of x + 40% of x=?
...
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