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ATQ,
Let the cost price of article 'C' = Rs. '10x'
Then, cost price of article 'D' = Rs. (10x + 40)
Sum of cost price of articles 'C' and 'D' = 10x + 10x + 40 = Rs. (20x + 40) = 350 × 2
Or, 20x + 40 = 700
Or, 20x = 660
Or, x = 33
Cost price of articles 'C' and 'D' are Rs. 330 and Rs. 370, respectively
Selling price of article 'C' = 330 × 1.18 = Rs. 389.4
Selling price of article 'D' = 370 × 1.22 = Rs. 451.4
Required difference = 451.4 - 389.4 = Rs. 62
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