Question
The cost price of gadget ‘B’ is (150/6)% of the selling
price of gadget ‘A’. Gadget ‘A’ is sold at 25% profit, and the cost price of gadget ‘A’ is Rs. 12 more than that of gadget ‘B’. If the cost price of gadget ‘A’ is equal to the selling price of gadget ‘B’, find the cost price of gadget ‘B’.Solution
ATQ,
Let cost price of gadget ‘A’ = Rs. ‘x’ = selling price of gadget ‘B’
Selling price of gadget ‘A’ = 1.25 × x = Rs. ‘1.25x’
Cost price of gadget ‘B’ = (3/12) × 1.25x = Rs. ‘0.3125x’
ATQ,
x = 0.3125x + 12
Or, 0.6875x = 12
Or, x = 17.45
So, cost price of gadget ‘B’ = 0.3125x = 0.3125 × 17.45 ≈ Rs. 5.45
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
