Question
Cost price of article ‘B’ is (250/7)% of selling price
of article ‘A’. Article ‘A’ is sold at 40% profit and cost price of article ‘A’ is Rs. 15 more than that of article ‘B’. Find the cost price of article ‘B’ if the cost price of article ‘A’ is the same as the selling price of article ‘B’.Solution
ATQ,
Let cost price of article ‘A’ = Rs. ‘x’ = selling price of article ‘B’
Selling price of article ‘A’ = 1.40 × x = Rs. ‘1.4x’
So, cost price of article ‘B’ = (5/14) × 1.4x = Rs. ‘0.5x’
ATQ,
x = 0.5x + 15
Or, 0.5x = 15
Or, x = 30
So, cost price of article ‘B’ = 0.5x = 0.5 × 30 = Rs. 15
25, 200, 40, ?, 64, 512
14, 28, 54, 98, 154, 224
18, 25, 33, 42, 52, 63, ?
1 2 9 ? 65 126
...98 148 185 ? 228 238
20 9 10 ? 29 71.5
...Each question below is based on a number series. Identify the pattern and answer accordingly.
A sequence {Tₙ} is defined as:
T₁ = a, T...
22 15 10 20 33 93.5
...The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
5 14 56 220 1125 6786
...
