Question
The cost price of product ‘B’ is (400/9)% of the
selling price of product ‘A’. Product ‘A’ is sold at 35% profit, and the cost price of product ‘A’ is Rs. 18 more than that of product ‘B’. If the cost price of product ‘A’ is equal to the selling price of product ‘B’, find the cost price of product ‘B’.Solution
ATQ,
Let cost price of product ‘A’ = Rs. ‘x’ = selling price of product ‘B’
Selling price of product ‘A’ = 1.35 × x = Rs. ‘1.35x’
Cost price of product ‘B’ = (4/9) × 1.35x = Rs. ‘0.6x’
ATQ,
x = 0.6x + 18
Or, 0.4x = 18
Or, x = 45
So, cost price of product ‘B’ = 0.6x = 0.6 × 45 = Rs. 27
The perimeter of a square field is 14 cm more than the perimeter of a rectangle. The length of the rectangle is 49 cm which is 350% of its width. If a s...
A rectangular tank is 50 meter long and 29meter deep. If 1000 cubic meters of water be drawn off the tank, the level of the water in the tank goes down ...
A can do a certain work in 12 days, B alone can do the same work in 16 days. A and B undertook to complete it in Rs. 8000. With the help of C, they comp...
The average presence of students of a class in a College on Monday, Tuesday and Wednesday is 32 and on the Wednesday, Thursday, Friday and Saturday is 3...
If the area of a square field is 625 m2, then find the diagonal of the square field.
Find the volume (in cm³) of a right circular cone whose diameter is 30 cm and height is equal to the radius of a circle whose circumference is 110 cm. ...
A hemispherical bowl of internal radius 9 cm, contains a liquid. This liquid is to be filled into small cylindrical bottles of diameter 3 cm and height ...
If the side of square and its area is in the ratio of 7:28 then find its perimeter?
Ratio of length to width of a rectangular field is 4:3. If the perimeter of the field is 140 metres, then find the area (in m2) of the field.
- Determine the diameter of the incircle of a triangle where the semi-perimeter is 22 cm and the area is 66 cm².
