Question
The ratio of cost price to the marked price of an
article is 5:8. The article had been marked above its cost price by Rs. 300. If the article was sold at a discount of Rs. 180, then find the profit/loss percentage incurred.Solution
Let the cost price and marked price of the article be Rs. 5x and Rs. 8x, respectively
According to the question,
8x – 5x = 300
Or, x = 100
Therefore, cost price of the article = 5x = Rs. 500
Marked price of the article = 8x = Rs. 800
Selling price of the article = 800 – 180 = Rs. 620
Required profit percentage = {(620 – 500)/500} × 100 = 24%
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
l). 3p + 2q = 27
ll). 4p - 3q = 2
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 38x + 352 = 0
Equation 2: y² - 38y + 312 = 0
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
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I. x
Find the maximum value of f(x)= –2x² +8x + 3.
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...
