Question
Person 'P' purchased two watches
at the same price. One of the watches was sold at a profit of 26%, while the other was sold at a loss of 36%. The difference between the selling prices of the two watches amounts to Rs. 3100. Determine the profit that 'P' would earn if he sold one of the watches at a profit of 36%.Solution
ATQ, Let the cost price of each watch be Rs. '100x'. So, selling price of first watch = Rs. 100x × 1.28 = Rs. '128x' Also, selling price of second watch = Rs. 100x X 0.64 = Rs. '64x' ATQ, (128x - 64x) = 3100 Or, 62x = 3100 So, 'x' = 50 Cost price of the watch = Rs. 100 × 50 = Rs. 5000 Therefore, the required price = 5000 × 0.36 = 1800
30.01 × √1023 + 196 = ? 2 – 287
70.008% of 399.98 + ?% of 399.999 = 80.105% of 599.998
? = 26.08 + 18.99 × 25.07
A bag contains 25 white and some black balls. If the probability of drawing a black ball from the bag is thrice that of drawing a white ball, fin...
 15.78% of (287 + 302) + 12³ = ?% of 170 + 8 × 14 + 3²Â
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
A certain sum of money invested at R% p.a. fetches a compound interest (compounded annually) of 1620 and simple interest of Rs.1500 at the end of 2 year...
4650.12 ÷ √8648.88 + √27.08 * √1727.85 = ? – 609.10 ÷ 87.07                     Â
...(439.98 ÷ 10.99) × 23.98= ? × (23.98) 2 ÷ 47.98
29.88% of 3599.90 + 5/12 of 2399.81 – 34.81% of 1200.18 = ?
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