Question
A trader bought 1200 items at ₹50 each. He sold half
of them at a profit of 20%, and the remaining half at a profit of 25%. Find the overall profit percentage.Solution
Cost price for 1200 items = 1200 × 50 = ₹60,000. Selling price for first half (600 items) = 600 × 50 × 1.20 = ₹36,000. Selling price for second half (600 items) = 600 × 50 × 1.25 = ₹37,500. Total selling price = ₹36,000 + ₹37,500 = ₹73,500. Profit = ₹73,500 - ₹60,000 = ₹13,500. Profit percentage = (13,500 / 60,000) × 100 = 22.5%. Correct answer: a) 22.5%.
Given that (3a + 7b = 54) and (ab = 24), determine the value of (9a2 + 49b2).
The certain sum amounts to Rs11313.5 in 2(1/2) years at 12% p.a., interest compounded 10 months. The sum (in Rs) is:
Find the number of zeroes in 18 × 125 × 20 × 32.
If (2a + b)/(3b - 2b) = 13/2 then 'b' is what percent of 'a'?
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= ?If (a + b) = 17 and (a2 + b2) = 145, then find the value of (a × b).
If x² + y² + z² = xy + yz + zy (x≠0), then the value of (5x+3y-4z)/2x is
when x =4 and y =-6 then find the value of 27x³ +58x²y +31xy² +8y³?
What will come in the place of question mark (?) in the given expression?
?2 = (392 × 224) ÷ (112 × 28) + 62
