Question
A constant retarding force of 20 N is applied to a body
of mass 10 kg moving initially with a speed of 12 m s–1. How long does the body take to stop?Solution
Given that Retarding force, F = – 20 N Mass of the body, m = 10 kg Initial velocity of the body, u = 12 m /s Final velocity of the body, v = 0 Using Newton’s second law of motion, the retardation (a) produced in the body can be calculated as: F = ma – 20 = 10 × a ∴ a = −20/10 = − 2 m/s2 Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as v = u + at ∴ t = -u/a =  −12/−2 = 6 seconds Hence time taken by the body to come to rest is 6 seconds
Self-Determination Theory is a theory of motivation and personality that addresses three universal, innate and psychological needs these are
 ...
 Which of the following statements is/are true about the National Stock Exchange of India (NSE)?
1)It is a government-owned stock exchange.
...Which of the following factors affecting the cost of capital can be controlled by the firm?
Under the IBC, which of the following is NOT a condition for MSMEs to qualify for insolvency resolution?
Which of the following are considered primary securit y in the context of CGTMSE?  Â
Who is the current chairperson of SIDBI?
AD Category – I banks are required to report all the inward remittances including advance as well as old outstanding inward remittances received for e...
What is "Flipping" in the context of entrepreneurship?
If an individual is unable to pay back the overdraft taken by him, which of the following risk is the bank facing?
The sweat equity shares issued to directors or employees have a lock-in of what duration?
Relevant for Exams:
