📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!

    âš¡ Month End Offer - Flat 52% Off On All Courses! Enroll Now âš¡
    00:00:00 AM Left

    Question

    A constant retarding force of 20 N is applied to a body

    of mass 10 kg moving initially with a speed of 12 m s–1. How long does the body take to stop?
    A 5 sec Correct Answer Incorrect Answer
    B 7 sec Correct Answer Incorrect Answer
    C 4 sec Correct Answer Incorrect Answer
    D 6 sec Correct Answer Incorrect Answer

    Solution

    Given that Retarding force, F = – 20 N Mass of the body, m = 10 kg Initial velocity of the body, u = 12 m /s Final velocity of the body, v = 0 Using Newton’s second law of motion, the retardation (a) produced in the body can be calculated as: F = ma – 20 = 10 × a ∴ a = −20/10 = − 2 m/s2 Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as v = u + at ∴ t = -u/a =  −12/−2 = 6 seconds Hence time taken by the body to come to rest is 6 seconds

    Practice Next
    More General science Common Questions

    Relevant for Exams:

    ask-question