Question
A watch and a calculator were purchased with their cost
prices in a ratio of 2:1, respectively. The calculator was sold at a 25% loss, and the watch was sold at a 40% profit. The combined transactions resulted in an overall profit of Rs. 110 for the shopkeeper. Calculate the original cost price of the watch.Solution
Let the cost price of the watch and the calculator be Rs. ‘2x’ and Rs. ‘x’, respectively. Selling price of the watch = 2x × 1.4 = Rs. ‘2.8x’ Selling price of the calculator = x × 0.75 = Rs. ‘0.75x’ ATQ; (2.8x + 0.75x) – (2x + x) = 110 Or, 3.55x – 3x = 110 Or, 0.55x = 110 So, x = 200 So, cost price of the watch = 200 × 2 = Rs. 400 Hence, option b.Â
What will come in the place of question mark (?) in the given expression?
? = (40% of 80% of 6400) ÷ 64
420 ÷ 7 + 140 % of 20 + ? × 13 = 18 × 15
Determine the simplified value of the expression: 12 × 15 - 20 + 15 + 12 - 18 + 3 × 4 + 18.
15% of 1800 + 22 = ?Â
Solve the following:
523 + 523 x 523 ÷ 523
24% of 150% of 500 + 140 = ? × 8Â
[∛(3375/19683  )- ∛(125/1728  )  ] ÷ ∛(64/729)  = ? - 3/8Â
7, 8, 12, 21, 37, ?
What value should come in the place of (?) in the following questions.
336 ÷ 6 ÷ √16 * ? = 1400 ÷ 4
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