Question
The cost price of two laptops 'L' and 'K' is Rs. 35,000
and Rs. 45,000 respectively. The shopkeeper marked up the prices of laptop 'L' and 'K' by 35% and 65% respectively. Laptop 'L' is sold after allowing a discount of 18% while laptop 'K' is sold at a profit of 22%. Which of the following statement(s) is/are false according to the given data? (I) Selling price of laptop 'L' is Rs. 33,320. (II) Discount offered on buying laptop 'K' is 22%. (III) Profit earned on selling laptop 'K' is more than that on selling laptop 'L'.Solution
ATQ, Marked price of laptop 'L' = 135% of 35,000 = (1.35) x 35,000 = Rs. 47,250 Selling price of laptop 'L' = 82% of 47,250 = (0.82) x 47,250 = Rs. 38,745 Profit earned on laptop 'L' = Rs. 38,745 - Rs. 35,000 = Rs. 3,745 Marked price of laptop 'K' = 165% of 45,000 = (1.65) x 45,000 = Rs. 74,250 Selling price of laptop 'K' = 122% of 45,000 = (1.22) x 45,000 = Rs. 54,900 Discount offered on laptop 'K' = (19,350/74,250) x 100 = 26.05% Statement (I) is false (the selling price of laptop 'L' is Rs. 38,745, not Rs. 33,320). Statement (II) is false (the discount on laptop 'K' is 26.05%, not 22%). Statement (III) is true (Rs. 9,900 profit on laptop 'K' is more than Rs. 3,745 on laptop 'L').
Simplify: 3/4 + 0.6 − (1/5 × 1.5)
The top part (numerator) of a fraction is 4 more than three times the bottom part (denominator). If we reduce the numerator by 15 and increase the denom...
Simplify: 1.5 + 2.25 − 0.75 ÷ 0.25
Evaluate: 4.8 × 2.5 + 9.6 ÷ 0.4
Calculate: 0.48 ÷ 0.12 + 2.5 × 0.4 − 0.35
A man distributed some candies to his three sons A, B and C. A, being the eldest got two times the number of candies that C got while A and B together h...
Evaluate: 180 ÷ (6 × 5) + 7 × 3 − 8
If the numerator of a fraction is increased by 25% and the denominator is decreased by 10%, the value of the new fraction 25/24, Find the original faction.
If log₁₀(x + 3) − log₁₀(x − 1) = 1, find the value of x.