Question
Ravi purchased 6 notebooks, 18 markers, and 12
highlighters for Rs. 240, Rs. 1080, and Rs. 360, respectively, from a seller. By selling each notebook and each marker, the seller made a profit of ‘c%’ and ‘d%’, respectively, such that d = 2c. Find the profit earned by the seller on selling all the highlighters given the condition that the cost price of a marker, a notebook, and a highlighter is the same.Solution
According to the question Let the cost price of each notebook, each marker, and each highlighter be Rs. ‘y’ Selling price of each notebook = (240/6) = Rs. 40 Selling price of each marker = (1080/18) = Rs. 60 According to the question, (40–y)/y×100=c…… (I) Also, (60–y)/y×100=d…… (II) Dividing equation (I) by (II), we get (40–y)/(60–y)=c/d Or, (40–y)/(60–y)=c/2c Or, 80y–2y=60–y Or, y=20 Therefore, the cost price of all the highlighters = Rs. 12y = Rs. 240 Required profit = 360 – 240 = Rs.120
Solve the quadratic equations and determine the relation between x and y:Â
Equation 1: 2x² - 10x + 12 = 0
Equation 2: y² - 8y + 15 = 0
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