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According to the question Let the cost price of each notebook, each marker, and each highlighter be Rs. ‘y’ Selling price of each notebook = (240/6) = Rs. 40 Selling price of each marker = (1080/18) = Rs. 60 According to the question, (40–y)/y×100=c…… (I) Also, (60–y)/y×100=d…… (II) Dividing equation (I) by (II), we get (40–y)/(60–y)=c/d Or, (40–y)/(60–y)=c/2c Or, 80y–2y=60–y Or, y=20 Therefore, the cost price of all the highlighters = Rs. 12y = Rs. 240 Required profit = 360 – 240 = Rs.120
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