A seller marked the price of an item at Rs. 6,000. The

Solution

ATQ; SP of the item = 6000 × (1 - (c + 6)/100) × (1 - (c - 6)/100) = 4848 or, {(100 - c - 6)/100} × {(100 - c + 6)/100} = 4848/6000 or, (94 - c) × (106 - c) = (4848/6000) × 100 × 100 or, 94 × 106 - 94c - 106c + c² = 8092 or, c² - 200c + 9964 - 8092 = 0 or, c² - 200c + 1872 = 0 or, c² - 10c - 190c + 1872 = 0 or, c × (c - 10) - 187 × (c - 10) = 32 or, (c - 10) × (c - 187) = 32 So, c = 10 or c = 187 But, c = 187 is not possible because the discount cannot be more than 100%. Therefore, c = 10