Question
Aman bought two articles for Rs. 840. He sold one at a
loss of 20% and another at a profit of 20%. If the selling price of both the articles is equal, then find the difference between their cost prices.Solution
ATQ, Let the cost price of the two articles be Rs. x and Rs. y respectively. Selling price of the first article = 0.80 × x = Rs. 0.80x Selling price of the other article = 1.20 × y = Rs. 1.20y According to the question, 0.80x = 1.20y x/y = 1.20/0.80 = 3/2 Desired difference = (3 – 2)/5 × 840 = 0.20 × 840 = Rs. 168
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