Question
The article is sold at a profit of 50%. If the
purchasing price doubles and the selling price halves, what will be the percentage of profit or loss?Solution
Let CP = 100 Profit = 50% Sp = 150 So now CP is double, and the selling price is half. then CP= 200 SP = 75 Loss = 200-75= 125 Loss% = (125/200) ×100 =62.5%
I.8(x+3) +Â 8(-x) =72Â
II. 5(y + 5) + 5(-y) = 150Â
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 3p² - 11p + 10 = 0
II. 2q² + 13q + 21 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. p2 + 2p – 8 = 0 II. q2 – 5q + 6 = 0
I. 7x + 8y = 36
II. 3x + 4y = 14
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. x=  √(20+ √(20+ √(20+ √(20…………….∞)) ) )Â
II. y= √(5√(5√(5√(5……….∞)) ) )Â
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 20y + 96 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
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