Question
One article is sold at 16% profit while other is sold at
5% loss such that the difference between their selling prices is Rs. 126. If the cost price of both the articles is same, then find the selling price of article sold at profit.Solution
Let the cost price of both the articles be Rs. x According to the question, 1.16x – 0.95x = 126 Or, x = 126/0.21 Or, x = Rs. 600 Therefore, selling price of articles sold at profit = 1.16x = Rs. 696
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 7p + 8q = 80
II. 9p – 5q = 57
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. (4x-5)3Â +Â 1/(4x-5)3Â = 2
II. 2[(y+1/y)2- 2]- 9(y+1/y)= -14
If 3x – 2y = 10 and xy = 11, the value of 27x³ – 8y³ is __________.
I. 9x2 + 45x + 26 = 0
II. 7y2 – 59y − 36 = 0
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
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