Question
A shopkeeper purchased an article for Rs. ‘a’ and
marked it 140% above its cost price and sold it after giving two successive discounts of Rs270 and 20%, respectively and earned a profit of Rs. 4a/5. Find the marked price of the article.Solution
Selling price of the article = a + (4a/5) = Rs. (9a/5) So, (9a/5) = (2.4 × a – 270) × 0.80 Or, 1.8a = (2.4a – 270) × 0.80 Or, 2.25a = 2.4a – 270 Or, 0.15a = 270 Or, a = 1800 So, marked price of the article = 2.4 × 1800 = Rs. 4320
A $ B means A X B, A & B means A - B, A % B means A ÷ B and A # B means A + B, then what is the value of 320 & 80 # 120 % 24 $ 50?
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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