Question
Axe and Wye purchases the Bikes at same price and later
on Zed purchase both the bikes at the same price of Rs. 72000. But the profit % of Axe was A% while profit % of Wye was B% since Wye calculate his profit on SP, if Zed sells one of the Bike to Pee at A% profit. What is the cost price for Pee if B= 41(2/3)% A?Solution
Let the Cost Price for Axe and Wye be x SP for both Axe and Wye = 72000 CP for Zed = 72000 (1 mobile) Profit for Axe = A% Profit for Wye = B% = 41*2/3% A = A ×125/(3 ×100) = A × 5/12 Now, the amount of profit for Axe and Wye is same Therefore, x × A/100 = 72000 × A × 5/12 ×1/100 x = 30000 Cost price for Axe and Wye is 30000 For Axe : CP = 30000 SP = 72000 Profit = 72000 – 30000 = 42000 Profit % for Axe = 42000/30000 × 100 = 140% For Zed : CP = 72000 Profit = 72000 × 140% = 100800 SP = 100800 + 72000 = 172800 Therefore, Cost price for Pee = 172800
193. 69 + 200.09 – 512.96 + 312.09 =?
What will come in the place of question mark (?) in the given expression?
224 ÷ 8 + 480 ÷ 15 = ? ÷ 2 – 270 ÷ 18
(96% of 1100) + 92 × 4 = ? + 46 × 16
15% of 2400 + (√ 484 – √ 256) = ?
140% of 75 + 152 - 160 = ?
(560 ÷ 32) × (720 ÷ 48) = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
?3 - 25 × 11 = 30 - 15 × 12
√? = 32% of 900 + 48% of 50
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