Question

A bag has ((x + 1)) red, ((x + 4)) green and ((x + 7)) yellow balls. Find the probability of taking, without replacement, out 2 red, 2 green and 1 yellow ball if the probability of taking out 1 yellow ball at random from the bag is ((5/12)).

A 45/476
B 47/476
C 51/476
D 55/476
E 59/476
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