Question
A game consists of tossing three coins once and then
rolling two dice. Find the probability of getting exactly two heads in the coin toss and a sum equal to 7 on the dice.Solution
For tossing 3 coins: Total number of possible outcomes = 23 = 8 Number of favourable outcomes = 3 (HHT, HTH, THH) So, probability of getting two heads while tossing three coins = (3/8) For rolling 2 dice: Total number of possible outcomes = 6 × 6 = 36 Number of favourable outcomes = 6 [(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)] So, Probability of getting a sum equal to 7 while rolling 2 dice = (6/36) = (1/6) Required probability = (3/8) × (1/6) = 1/16
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