Question
A 6-digit number is formed using the digits 1, 2, 3, 4, 5
and 6. If each digit can be used only once, then find the probability that the number formed will be divisible by 4.Solution
Total numbers formed = 6! = 720
For divisibility by 4, the last two digits of the number must form a number divisible by 4
From digits 1–6, valid 2-digit endings divisible by 4 without repetition are: 12, 16, 24, 32, 36, 52, 56, 64 → total = 8 combinations
For each, remaining 4 digits can be arranged in 4! = 24 ways
Total such numbers = 8 × 24 = 192
Required probability = 192/720 = 4/15
What is the requirement for a person to acquire or hold more than five percent of the paid-up equity share capital of a depository, as mentioned in Reg...
Comptroller and Auditor General of India shall be removed-
The principle of confidentiality in the Arbitration and Conciliation Act, 1996 is laid down in
Which of the following is not an essential of partnership ?
What was held in the case of Hansia vs Bhaktawramal?
Which section of Hindu Succession Act mentions that the property of a female Hindu is to be her absolute property?
Under Section 47(2) of the BNSS, 2023, what must a police officer inform a person arrested without warrant for a bailable offence?
 According to the Recovery of Debts and Bankruptcy Act, 1993 on and from the appointed day, no court or other authority shall have, or be entitled to ...
Which Article of the Constitution talks about directive principles of State policy for protection of wildlife?
An Offer must be:
