Question
A 5-digit number is created using the digits 2, 3, 4, 5, and 6 without repetition. What is the probability that the number is divisible by 5?
Solution
ATQ,
Total numbers formed = 5! = 120 For divisibility by 5, the number must end in either 0 or 5. But 0 is not among the digits, so only 5 can be at the unit place. Fix 5 at the end → Remaining 4 digits can be arranged in 4! = 24 ways Total such numbers formed = 24 × 1 = 24 Required probability = 24 / 120 = 1 / 5
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