Question
Bag A contains 3 yellow and 5 blue balls, while Bag B
contains 4 yellow and 6 green balls. If one ball is drawn from bag 'A' and bag 'B', respectively, at random, then what is the probability that both balls drawn are yellow?Solution
Probability of drawing a yellow ball from Bag A = (3/8)
Probability of drawing a yellow ball from Bag B = (4/10)
Required probability = (3/8) × (4/10) = (12/80) = (3/20)
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