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    Question

    A bag contains 10 white balls, 4 red balls and 6 black

    balls. Three balls are drawn at random. Find the probability that at least two balls are red.
    A (49/285) Correct Answer Incorrect Answer
    B (5/57) Correct Answer Incorrect Answer
    C (23/114) Correct Answer Incorrect Answer
    D (7/95) Correct Answer Incorrect Answer
    E (13/152) Correct Answer Incorrect Answer

    Solution

    Total = 10 + 4 + 6 = 20
    Required probability = (Two red and one other) + (Three red)

    = 3 ├Ч [(4/20) ├Ч (3/19) ├Ч (16/18)] + (4/20 ├Ч 3/19 ├Ч 2/18)
    = (576/6840) + (24/6840)
    = (600/6840) = (5/57)

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