Question
A bag contains 10 white balls, 4 red balls and 6 black
balls. Three balls are drawn at random. Find the probability that at least two balls are red.Solution
Total = 10 + 4 + 6 = 20
Required probability = (Two red and one other) + (Three red)
= 3 × [(4/20) × (3/19) × (16/18)] + (4/20 × 3/19 × 2/18)
= (576/6840) + (24/6840)
= (600/6840) = (5/57)
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