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      Question

      A bag contains 8 blue balls, 7 green balls and 5 yellow

      balls. Three balls are drawn at random. Find the probability that at least two balls are green.
      A (23/114) Correct Answer Incorrect Answer
      B (7/34) Correct Answer Incorrect Answer
      C (77/285) Correct Answer Incorrect Answer
      D (4/19) Correct Answer Incorrect Answer
      E (18/95) Correct Answer Incorrect Answer

      Solution

      Total balls = 8 + 7 + 5 = 20
      Required probability = (Two green and one other) + (Three green)

      = 3 Γ— [(7/20) Γ— (6/19) Γ— (13/18)] + (7/20 Γ— 6/19 Γ— 5/18)
      = (1638/6840) + (210/6840)
      = (1848/6840) = (77/285)

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