Question
The probability that Kunal passes an exam is (5/11) and the
probability that Tanya fails is (3/7). If both write the exam, what is the probability that they both have the same result?Solution
Probability that Kunal fails = 1 - (5/11) = (6/11)
Probability that Tanya passes = 1 - (3/7) = (4/7)
Required probability = (5/11) × (4/7) + (6/11) × (3/7)
= (20/77) + (18/77) = (38/77)
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