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    Question

    Dravid who is playing a game with his younger brother threw

    a dice three times. What is the probability of getting at least four on each attempt?
    A 1/6 Correct Answer Incorrect Answer
    B 1/3 Correct Answer Incorrect Answer
    C 1/8 Correct Answer Incorrect Answer
    D 8/27 Correct Answer Incorrect Answer
    E 1/27 Correct Answer Incorrect Answer

    Solution

    There are six numbers on a dice so when Dravid throws the dice then there can be 6 outcomes.
    Now numbers which are greater than or equal to 4 are three, hence total favorable outcomes = 3
    Hence required probability when dice is thrown only once = 3/6=1/2
    When this process is repeated thrice then the required probability = 1/2 X 1/2 X 1/2 = 1/8

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