Question
Dravid who is playing a game with his younger brother threw
a dice three times. What is the probability of getting at least four on each attempt?Solution
There are six numbers on a dice so when Dravid throws the dice then there can be 6 outcomes.
Now numbers which are greater than or equal to 4 are three, hence total favorable outcomes = 3
Hence required probability when dice is thrown only once = 3/6=1/2
When this process is repeated thrice then the required probability = 1/2 X 1/2 X 1/2 = 1/8
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