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      Question

      Dravid who is playing a game with his younger brother threw

      a dice three times. What is the probability of getting at least four on each attempt?
      A 1/6 Correct Answer Incorrect Answer
      B 1/3 Correct Answer Incorrect Answer
      C 1/8 Correct Answer Incorrect Answer
      D 8/27 Correct Answer Incorrect Answer
      E 1/27 Correct Answer Incorrect Answer

      Solution

      There are six numbers on a dice so when Dravid throws the dice then there can be 6 outcomes.
      Now numbers which are greater than or equal to 4 are three, hence total favorable outcomes = 3
      Hence required probability when dice is thrown only once = 3/6=1/2
      When this process is repeated thrice then the required probability = 1/2 X 1/2 X 1/2 = 1/8

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