Question
Dravid who is playing a game with his younger brother threw
a dice three times. What is the probability of getting at least four on each attempt?Solution
There are six numbers on a dice so when Dravid throws the dice then there can be 6 outcomes.
Now numbers which are greater than or equal to 4 are three, hence total favorable outcomes = 3
Hence required probability when dice is thrown only once = 3/6=1/2
When this process is repeated thrice then the required probability = 1/2 X 1/2 X 1/2 = 1/8
Find the missing number.
Find the missing number.
Select the number from the given option that can replace the question mark (?) in the following series:
32, 16, 24, 60, ?, 945
Find the missing term?
Select the missing number from the given responses:
Select the number which can be placed in the column of question mark sign.
Select the option that is related to the third number in the same way as the second number is related to the first number.
15 : 5 :: 26 : (?)
What number should replace the question mark?Â
Select the number that can replace the question mark (?) in the following series.Â
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