Question
There are 2 boxes. Box A contains 6 gums and 4 candies and
Box B contains 3 gums and 7 candies. If a box is selected at random and 2 things are drawn out of it, what is the probability that they are different?Solution
Required probability= P(Box A is selected, 1 gum, 1 candy) +P(Box B is selected, 1 gum, 1 candy)
= (1/2)*( 6 C 1 )( 4 C 1 )/( 10 C 2 ) + (1/2)*( 3 C 1 )( 7 C 1 )/( 10 C 2 ) = 1/2
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