Question
A fair coin is tossed 6 times. What is the probability
of getting exactly either two or three heads?Solution
Since a fair coin is tossed 6 times hence total number of possible outcomes = 2 6 Â = 64
Total number of ways of getting either two or three heads = 6C2 Â +Â 6C3 Â = (15 + 20) = 35
Hence required probability = 35/64
 If the PV ratio us 80% and MOS is 20000. Calculate FC if SP per unit is 5 and Contribution is 40000.
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