Question
A fair coin is tossed 6 times. What is the probability
of getting exactly either two or three heads?Solution
Since a fair coin is tossed 6 times hence total number of possible outcomes = 2 6 = 64
Total number of ways of getting either two or three heads = 6C2 + 6C3 = (15 + 20) = 35
Hence required probability = 35/64
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