Question
A box contains 6 red, 5 green, and 4 blue balls. Two
balls are drawn randomly. What is the probability that they are of different colors?Solution
Total number of ways to choose 2 balls: 15C2 = 105 Favorable cases: Red-Green: 6 × 5 = 30 Red-Blue: 6 × 4 = 24 Green-Blue: 5 × 4 = 20 Total favorable cases = 30 + 24 + 20 = 74 Probability = 74/105 Correct answer: d.
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
