Question
A box contains 6 red, 5 green, and 4 blue balls. Two
balls are drawn randomly. What is the probability that they are of different colors?Solution
Total number of ways to choose 2 balls: 15C2 = 105 Favorable cases: Red-Green: 6 × 5 = 30 Red-Blue: 6 × 4 = 24 Green-Blue: 5 × 4 = 20 Total favorable cases = 30 + 24 + 20 = 74 Probability = 74/105 Correct answer: d.
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