Question
A bag contains 3 white balls , 5 blue balls , and 8 red
balls . One ball is picked randomly from the bag and discarded. What is the probability of selecting a red ball from the remaining balls?Solution
Required probability: = Probability of drawing (White in first, Red in second) + Probability of drawing (Blue in first, Red in second) + Probability of drawing (Red in first, Red in second) = (3/16) X (8/15) + (5/16) X (8/15) + (8/16) X (7/15) = (24/240) + (40/240) + (56/240) = (120/240) = (1/2)
9/5 × 18/25 ÷ 42/21 = ? - 82/75
15 × 18 + 25 × 12 + 30 × 24 = ?% of 1720
√324 * 6 – 20% of 180 + ? = 130% of 150
400 % of 20 + 65 % of 620 - 92 × 5 = ?
- Find the value of the expression:
15 + 10 – 6 × [20 + 8 – 2 × (50 – 35)] What will come in place of (?) in the given expression.
(3/4 of 64) + (1/2 of 48) = ?If 1210 ÷ 22 + 1332 ÷ 37 - y + 54 × 3 = 980 ÷ 20 × 144 ÷ 48, then the value of y is:
600 ÷ 8 + 12 % of 250 + ? * 14 = 50 * √49
What will come in the place of question mark (?) in the given expression?
23 X 35 - ? = (132 + 16) X 3 + 25
- What will come in the place of question mark (?) in the given expression?
435 + 729 - 282 x 2 = ? + 225 + 125
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