Question
A person can hit a target 3 times out of 8 shots. If he
fires 10 shots, what is the probability that he will hit the target twiceSolution
n C r (P)r (1-P) n-r number of total shots (n) = 10 r = 2 Probability of hit shots = 3/8 Probability of not hit = 5/8 probability that he will hit the target twice = 10 C2 (3/8)2 (1-3/8) 10-2 = (10Ă—9/2) (3/8)2 (5/8)8 = (34Ă—59)/810
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