Question
Atul and Bhuvan play a game where each is asked to
select a number from 1 to 9. If the two numbers same, both win a prize. The probability that they will not win a prize in a single trial is:Solution
Total number of ways in which both can select a number each: = 9 × 9 = 81 Total number of ways in which both can select a same number so that they both can win: = 9 ways [They both can select {(1,1), (2,2), (3,3), (4,4), (5,5), (9,6), (7,7) (8,8) (9,9)}] Probability that they win the prize: = Favourable Cases/Total Cases = 9/81 = 1/9 Probability that they do not win a prize = 1 - 1/9 = 8/9.
Who among the following has been honoured with Sports Journalists' Federation of India (SJFI) Sportswoman of the Year 2021?
The________secrete(s) bile in human digestive system.
The number of Pawn in chess is_______.
Baburnama, the autobiography of Babur, was composed in______.
Where is the Great Divisioning Range located from the following countries?
Who is appointed as the President of the United States of America two times consecutively?
Who Chaired the 3rd FIPIC III Summit?
Which state in India celebrates the festival of Bihu?
Where was the Intercontinental Football Cup 2023 organised?
What is the average temperature of Human body?