Question
There are two bags P and Q. Bag P contains 5 Yellow and
6 Green balls while bag Q contains 6 Yellow and 5 Green balls. As a part of an experiment, a fair dice is rolled. If the face 2 or 5 turns up, a Green ball is taken from bag P and is then placed into bag Q. If any other face turns up, a Green ball is taken from bag Q and is then placed into bag P. The experiment is performed twice. What is the probability that total number of balls in bag P is not more than that in Bag Q after performing the experiments?Solution
Bag P will not have more number of balls than bag Q if we exclude the case where both the experiments result in placing Green balls in bag P. So, probability of bag P having total number of balls not more than Bag Q  = 1 – Probability of getting (1 or 3 or 4 or 6) during both the experiments = 1 – 4/6 × 4/6 = 5/9 Â
- Find the wrong number in the given number series.
25, 36, 29, 40, 33, 50 154Â Â Â Â 165Â Â Â Â 143Â Â Â Â 175Â Â Â Â Â 132Â Â Â Â Â 187
...5000, 4500, 3600, 2480, 1512, 756Â Â Â
Find the wrong number in the given number series,
125, 150, 250, 475, 875, 1500
- Find the wrong number in the given number series.
5, 8, 12, 19, 27, 39 768Â Â Â 2304Â Â Â 288Â Â Â 864Â Â Â 106Â Â Â 324
Find the wrong number in the given number series.
5, 6, 14, 45, 188, 925
120, 240, 80, 320, 60, 384
21 32 54 86 131 186
... 7    12     33    126    635  Â
Relevant for Exams:
