Question
From a standard pack of 52 cards, 3 cards are drawn at
random without replacement. The probability of drawing a king, a queen and a jack in order is.Solution
The probability of drawing a king, a queen and a jack in order is the product of the probabilities of drawing each card. There are 4 kings, 4 queens, and 4 jacks in a standard deck of 52 cards, so the probability of drawing any one of them is= 4/52. The first card can be any of the 3 cards in order. The probability of drawing a king first is.  The second card can be either a queen or a jack, but it cannot be the same as the first card.  There are 4 queens or jacks left, and 51 cards in total, so the probability of drawing the second card is =4/51 The same logic applies for the third card, and the probability of drawing a queen or a jack is =4/50  Therefore, the probability of drawing a king, a queen, and a jack in order is. =4/52× 4/51×4/50 =8/13×25×51= =8/16575
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â