Question
Two players, A and B, play a tennis match. It is known
that the probability of A winning the match is 0.65. What is the probability of B winning the match?Solution
Let S and R denote the events that A wins the match and B wins the match, respectively. The probability of Aβs winning =P(S) = 0.65(given) The probability of Bβs winning = P(R) = 1 β P(S) [As the events R and S are complementary] =1 β 0.65 = 0.35
(350/?) = 23 + 33
(630 Γ· 35) Γ 2 + 144 = ? Γ 2
?/4 ÷ 9/? = 15% of 800 + `1(2/3)` × `1(1/5)` × 1/2
236.23-653.23+696.23=?
72 Γ 2 = ? + 104 β 14
36895 - 4256 - 2233 = ?Β
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)? = 15% of 2400 + 140% of 4200 β 12 3Β
β121 + β961β β289 =?2
