Question
17 rotten bananas are accidentally mixed with 120 good
ones. It is not possible to just look at a banana and tell whether or not it is rotten. One banana is taken out at random from this lot. Determine the probability that the banana is taken out is a good one.Solution
Numbers of bananas = Numbers of rotten bananas + Numbers of good bananas ∴ Total number of bananas = 120 + 17 = 137 bananas P(E) = (Number of favourable outcomes) / (Total number of outcomes) P(picking a good banana) = 120/137
Statements: K ≥ R, M > T, M ≥ R, L = K < O
Conclusion:
I. M > K
II. O > R
Statements: R > U ≤ V = W ≥ S; T < M ≤ P = S
Conclusions:
I. V ≥ M
II. P < V
III. W ≥ T
Statements:
A ≤ B > E ≥ F; M > E < N
Conclusions:
I. N > F
II. B > F
Statements: R = S > Y ≥ T = W ≥ U > V > X
Conclusions:
I. Y < X
II. S > V
III. U ≤ RStatements: M * T, D % T, D # K, K $ R
Conclusions: I. M * DÂ Â Â Â Â II. T # KÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II...
Answer the following question based on the direction given below.
 If 'A#B' means 'A is equal to B'
'A@B' means 'A is greater than B'<...
In which of these expression ‘J > B’ is definitely True?
Statements: O > M = Q > S; M ≥ K > A; Q ≤ O < E
Conclusions: Â Â Â Â Â I. O > SÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. K < OÂ Â Â Â Â Â Â Â ...
Which of the following does not make J @ K and R # K definitely not true?
Statements: A = B ≥ C > D, F > G = H ≥ J, D ≥ E ≥ I > F
Conclusions:
I. D ≥ H
II. I > J
III. G < A
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