Question
A is trying to break a bulb by throwing balls at it. If
he hits the bulb 3 times in every 12 throws and bulb breaks 3 times out of 18 hits, then find the probability of A breaking the bulb.Solution
Probability of A hitting the bulb = 3/12 = 1/4 Probability of the bulb being broke on getting hit = 3/18 = 1/6 Probability of A breaking the bulb = (1/4) × (1/6) = 1/24
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
