Question
If a coin is tossed 10 times then what is the
probability of getting three heads?Solution
Total sample spaces = 2¹⁰ Total favourable events N(P) = ¹⁰C₃ Probability (E) = (N(P))/(N(S)) = (¹⁰C₃ )/(2¹⁰) = (¹⁰C₃ )/(2^5. 2⁵) = ((10 × 12 )/(3 × 2))/(32 × 32) = (10 × 12)/(32 × 32) = 15/128
More Probability Questions
49.99% of 639.99 + 159.98% of 49.99 = ?2
(5.013 – 30.04) = ? + 11.98% of 4799.98
(51.99² - 19.05² )÷ ? = 14.11² - 140.33
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
What approximate value will replace the question mark (?) in the following?
29.99...
(18.21)² - (12.9)² = 20% of 649.9 - ? + 400.033
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
39.9% of 1720 + 80.2% of 630 = 89.9% of 1280 + ?
(11.75)2 - 49.99% of 120 - ? = (8.23)2
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