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Total number of apples in the heap = n(S) = 1200 Let E be the event of selecting a rotten apple from the heap. Number of outcomes favourable to E = n(E) P(E) = n(E)/n(S) 0.22 = n(E)/1200 ⇒ n(E) = 1200 × 0.22 ⇒ n(E) = 264 Therefore, the number of rotten apples in the heap = 264
15.03% of (619.87 × 7) + (√399.63 × 16.11) ÷ 5 = ?
85.22 of 499.98% + 299.99 ÷ 30.18 = ?
(112.05 + 107.98) ÷ 11.04 + (12.05 × 4.99) ÷ 6 = ?
2090.03 ÷ 54.98 x 49.9 = ? + 20.32
244.98% of 189.98% of 599.99 + 199.98 = ?
620.15 + 1279.98 + ? × (4.79)2 = 149.95% of 1600.14
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009