Question

    There are 14 boys and 6 girls giving interview for a

    job. If three of them are selected, then what is the probability that one of the three is a girl and the other two are the boys?
    A 111/280 Correct Answer Incorrect Answer
    B 91/170 Correct Answer Incorrect Answer
    C 91/190 Correct Answer Incorrect Answer
    D 99/130 Correct Answer Incorrect Answer
    E 79/190 Correct Answer Incorrect Answer

    Solution

    Total Number of candidates = 20 Let ‘S’ be the Sample Space Then, n(S) = number of ways of three candidates who got selected n(S) = 20C3 = 1140 Let ‘E’ be the event of 1 girl and 2 boys selected Therefore, n(E) = number of possibility of 1 girl out of 6 and 2 boys out of 14 n(E) = 6C1 × 14C2 = 546 Now the required Probability = (n(E))/(n(S)) = 546/1140 = 91/190

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