Question
There are 14 boys and 6 girls giving interview for a
job. If three of them are selected, then what is the probability that one of the three is a girl and the other two are the boys?Solution
Total Number of candidates = 20 Let ‘S’ be the Sample Space Then, n(S) = number of ways of three candidates who got selected n(S) = 20C3 = 1140 Let ‘E’ be the event of 1 girl and 2 boys selected Therefore, n(E) = number of possibility of 1 girl out of 6 and 2 boys out of 14 n(E) = 6C1 × 14C2 = 546 Now the required Probability = (n(E))/(n(S)) = 546/1140 = 91/190
Eight people are sitting in two parallel rows containing 4 people each in such a way that there is equal distance between adjacent persons. In row 1, D,...
Three different positions of the same dice are shown. Find the number on the face opposite the face showing ‘6’.
Statements:
Some apples are oranges.
All oranges are fruits.
Conclusions:
I) All apples are fruits.
II) Some frui...
Which two numbers should be interchanged to make the following equation correct?
96 ÷ 8 − 3 × 6 + 32 = 24
Select the option figure that will replace the question mark (?) in the figure given below to complete the pattern.
‘F + R’ means ‘F is the mother of R’
‘F – R’ means ‘F is the father of R’
‘F ÷ R’ means ‘F is the husband of R’...
In a certain code language, ‘MUST’ is coded as ‘7913’ and ‘TALE’ is coded as ‘8672’.
What is the code for ‘T’ in the given co...
In a certain code language, 'LAST' is coded as 'PFWY'. What is the code for 'MEAN' in that code language?
Question Figure:
A, B, C, D, E, F, G and H are sitting around a square table, four of them sit at the 4 corners, while four sit at the middle of the sides. The ones who ...
Relevant for Exams:
