Question
Solution
ATQ, AC = β(15Β² + 20Β²) β AC = β(225 + 400) β AC = β625 β AC = 25 cm Now, find m(BD): m(BD) = (15 Γ 20) / 25 β m(BD) = 300 / 25 β m(BD) = 12 cm β΄ The length of BD is 12 cm.
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