The number nearest to 7658 and exactly divisible by 45

Solution

First, find the quotient when 7658 is divided by 45: Quotient = 7658 / 45 ⇒ Quotient = 170.1778 (approximately) Now, multiply the integer part of the quotient by 45: Nearest lower number divisible by 45 = 170 × 45 ⇒ 170 × 45 = 7650 Next, check the next number by adding 1 to the integer part of the quotient and multiplying by 45: Nearest higher number divisible by 45 = 171 × 45 ⇒ 171 × 45 = 7695 Now, compare the differences: Difference with 7650 = 7658 - 7650 = 8 Difference with 7695 = 7695 - 7658 = 37 Since 8 < 37, the number nearest to 7658 and exactly divisible by 45 is: 7650