Question
(cot θ + tan θ)(cosec θ − sin θ)(cos θ − sec
θ) = ________.Solution
We start by simplifying each term individually: ⇒ cot θ + tan θ = (cos θ/sin θ) + (sin θ/cos θ) ⇒ = (cos2 θ + sin2 θ) / (sin θ cos θ) ⇒ = 1 / (sin θ cos θ)           [since cos2 θ + sin2 θ = 1] Next, simplify cosec θ - sin θ: ⇒ cosec θ - sin θ = (1/sin θ) - sin θ ⇒ = (1 - sin2 θ) / sin θ ⇒ = cos2 θ / sin θ           [since 1 - sin2 θ = cos2 θ] Finally, simplify cos θ - sec θ: ⇒ cos θ - sec θ = cos θ - (1/cos θ) ⇒ = (cos2 θ - 1) / cos θ ⇒ = -sin2 θ / cos θ           [since cos2 θ - 1 = -sin2 θ] Now, combine all three simplified terms: ⇒ (cot θ + tan θ)(cosec θ - sin θ)(cos θ - sec θ) ⇒ = (1 / (sin θ cos θ)) × (cos2 θ / sin θ) × (-sin2 θ / cos θ) ⇒ = (1 / (sin θ cos θ)) × (cos2 θ / sin θ) × (-sin2 θ / cos θ) ⇒ = (-1)  [After simplifying the terms and canceling out common factors] ∴ The expression equals -1.
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