Question
In a fraction, three times the numerator is five more
than twice the denominator. If 3 is added to the numerator and denominator, the new fraction formed is 3/4. Find the original fraction.Solution
ATQ,
Let: Numerator = x, Denominator = y Given: 3x = 2y+5 
From 2nd equation: 4(x+3)=3(y+3)⇒4x−3y=−3 — (Eq A) From 1st: 3x−2y=5 — (Eq B) Solve Eq A & B: → y = 29 → x = 21 Hence, Original fraction = 21/29
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